A fraction becomes 1/3 if two is added to both numerator and denominator. If three is added to both numerator and denominator it becomes 2/5. Find the fraction.
Let numerator be x and denominator be y.
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When two is added to both numerator and denominator, the
fraction becomes
.
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3 (x + 2) = 1(y + 2)
3x + 6 = y + 2
3x – y = 2 – 6
3x – y = – 4 ……(1)
Now if 3 is added to both numerator and denominator fraction
becomes
.
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5 (x + 3) = 2 (y + 3)
5x + 15 = 2y + 6
5x – 2y = 6 – 15
5x – 2y = – 9 ……(2)
Eliminate equation (1) and (2)
(3x – y = – 4) × 2
(5x – 2y = – 9) × 1

x = 1
From equation (1) we have
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(∵ x = 1)
3 × 3 = y + 2
9 = y + 2
y = 7
∴ Numerator x = 1
Denominator y = 7
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