Three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one. Find the number.
Let three consecutive odd numbers be x, x + 2, x + 4
Eg - : If first odd number is one then other two will be 3 = 1 + 2 and 5 = 1 + 4
Smallest consecutive number = x
Largest consecutive number = x + 4
According to the question,
3x – 7 = 2(x + 4)
3x – 7 = 2x + 8
3x – 2x = 7 + 8
x = 15
First number = x = 15
Second number = x + 2 = 15 + 2 = 17
Third number = x + 4 = 15 + 4 = 19
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