Q24 of 54 Page 77

A father is 30 years older than his son. In 12 years the man will be three times as old as his son. Find their present ages.

Let the age of son be x and age of father be y.

Since father is 30 years older than his son


Therefore, father’s age = y = x + 30 ……(1)


After 12 years


Son’s age = x + 12


Father’s age = x + 30 + 12


= x + 42


After 12 years the man will be 3 times as old as his son


Therefore, father’s age = x + 42 = 3(x + 12)


x + 42 = 3x + 36


42 – 36 = 3x – x


6 = 2x


x = 3


Put in (1)


y = 3 + 30


y = 33


Therefore, son’s age is 3 years and father’s age is 33 years.


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