Q19 of 54 Page 77

Two years later a father will be 8 yrs more than three times the age of the son. Taking the present age of father and son as x and y respectively. Write a linear equation for the above.

Let father’s present age be x and son’s present age be y.

After two years


Son’s age = y + 2


Father’s age = x + 2


According to question


x + 2 = 8 + 3 (y + 2)


x + 2 = 8 + 3y + 6


x + 2 = 14 + 3y


x – 3y = 12


Equation is x – 3y = 12


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