Solve the linear equations x – 2y = 8 and 5x + 3y = 1 by algebraic method.
Equations:
x – 2y = 8 ……eq(i)
For elimination of one variable from both the equations, multiply the first equation by 5
(x – 2y = 8) ×5 = 5 x – 10 y = 40 ………eq(iii)
Subtracting eq(iii) from eq (ii)
5x + 3y – (5 x – 10 y) = 1 – 40
13 y = - 39
y = - 3
Putting the value of y in equation(i) we get,
x – 2 y = 8
x – 2 × (- 3) = 8
x + 6 = 8
x = 2.
Hence, Solution of the given linear equations are x = 2, y = - 3
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