Q36 of 54 Page 77

Sudesh is twice as old as Seema. If six years are subtracted from Seema's age and 4 years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they 3 years ago?

Let Sudesh’s age be x and Seema’s age be y.

According to the question,


x = 2y ……(1)


If 6 years are subtracted from Seema’s age then Seema's age = y – 6


If 4 years are added to Sudesh’s age then Sudesh’s age = x + 4


Now Sudesh is four times Seema's age


x + 4 = 4 (y – 6)


x + 4 = 4y – 24


Put value of x from (1)


2y + 4 = 4y – 24


4y – 2y = 24 + 4


2y = 26


y = 26/2


y = 13


Put y = 13 in (1)


x = 2y


x = 2 × 13


x = 26


Sudesh’s age 3 years ago = 26 – 3 = 23 years


Seema’s age 3 years ago = 13 – 3 = 10 years


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