Q41 of 54 Page 77

and 2 then find value of x and y.

Let's assume and

Now equation becomes


……(1)


5a + b = 2 ……(2)


Solving equations using substitution


b = 2 – 5a


Put value of b in (1)




– 13a = 3.4 – 6


– 13a = – 2.6



a = 0.2


Put a = 0.2 in (2)


5(0.2) + b = 2


1 + b = 2


b = 2 – 1


b = 1




3x + 2y = 5 ……(3)




3x – 2y = 1 ……(4)


Eliminate (3) and (4)


3x + 2y = 5


3x – 2y = 1


6x = 6


x = 1


Put x = 1 in (4)


3 – 2y = 1


2y = 2


y = 1


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