The digits of a two - digit number differ by 3. If the digits are interchanged and the resulting number is added to the original number we get 143. What can be the original number?
A 2 digit number can be expressed as 10 x + y, where x is the ten’s digit and y is the unit digit. For example:
16 = 1(10) + 6
It is given that the digits differ by 3
x – y = 3 ……(1)
When digits are interchanged, resulting number will be 10x + y
Resulting number + Original number = 143
10y + x + 10x + y = 143
11y + 11x = 143
11(x + y) = 143
x + y = 13 ……(2)
Eliminate (1) and (2) by adding both the equations
x – y = 3
x + y = 13
2x = 16
x = 8
Put x = 8 in (1)
8 – y = 3
y = 5
Original number = 10x + y
= 10×8 + 5
= 80 + 5
= 85
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