Q20 of 54 Page 77

A farmer counts nine heads and 24 legs of Chickens and cows. How many has each of these Chickens and cows?

Heads counted = 9

Legs counted = 24


Number of legs of a chicken = 2


Number of legs of a cow = 4


Let a number of chickens be x and number of cows be y.


Legs of chicken = 2x


Legs of cow = 4y


Total legs = 2x + 4y


2x + 4y = 24 divided by 2


x + 2y = 12 ……(1)


Both the chicken and cows have 1 head


Total heads = x + y


x + y = 9 ……(2)


Eliminate (1) and (2), Subtracting eq(2) from eq(1)


x + 2 y – ( x + y) = 12 – 9


y = 3


Putting value of y in equation 2,


x + y = 9


x + 3 = 9


x = 6


Therefore, there are 6 chickens and 3 cows.


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