Solve for u and v – : 2(3u – v) = 5uv and 2(u + 3v) = 5uv

Equation (1)

2 (3u – v) = 5uv

6u – 2v = 5uv ……(1)

Equation (2)

2 (u + 3v) = 5uv

2u + 6 v = 5uv ……(2)

Put value of 5uv from (1)

6u – 2v = 2u + 6v

6u – 2u = 6v + 2v

4u = 8v

u = 2v

Put u = 2v in (1)

6 (2v) – 2v = 5 (2v)v

12v – 2v = 10v²

v = 1

Also, u = 2v

u = 2 × 1

u = 2