Q13 of 153 Page 113

Two supplementary angles are in the ratio 3:2 Find the angles.

108°, 72°


Let angle = X


Supplementary of X = 180° – X


According to question,


X : 180° – X = 3 : 2


⇒ X / (180° – X) = 3 / 2


⇒ 2X = 3(180° – X)


⇒ 2X = 540° – 3X


⇒ 2X + 3X = 540°


⇒ 5X = 540°


⇒ X = 108°


Therefore angle = 108°


And its supplement = 180° – 108° = 72°


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