Q11 of 153 Page 166

In the given figure, BAD || EF, ∠AEF = 55° and ∠ACB = 25°, find ∠ABC.



According to question EF || BAD


Producing E to O, we get


EFA + AEO = 180 (Linear pair of angles)


AEO = 180 – 55


= 125


Now, in triangle ABC we get,


A = 125 and C = 25


So, ABC = 180 – (A + C)


= 180 – (125 + 25)


= 180 – 150


= 30O


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