Q42 of 153 Page 148

In the given figure, sides CB and BA of ΔABC have been produced to D and E respectively such that ∠ABD = 110° and ∠CAE = 135°. Then ∠ACB = ?

∠ABC = 180 – 110 = 700 (Linear pair of angles)


∠BAC = 180 – 135 = 450 (Linear pair of angles)


So,


In Triangle ABC, we have


∠ABC + ∠BAC + ∠ACB = 180o


∠ACB = 180 – 70 – 45 = 650

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