In the given figure, AB||PQ. Find the value of x and y.

x=70, y=50

Given AB||PQ

∠GEF + 20° + 75° = 180°[Because EF is a straight line]

⇒ ∠GEF = 180° - 95°

⇒ ∠GEF = 85°________________ (i)

In triangle EFG,

⇒ X + 25° + 85° = 180° [∠GEF = 85°]

⇒ X = 60°

Now,

⇒ ∠BEF + ∠EFQ = 180°[Because AB||PQ]

⇒ (20° + 85°) + (25° + Y) = 180°

⇒ Y = 180° - 130°

⇒ Y = 50°