In the given figure, AB || CD || EF. If ∠ABC = 85°, ∠BCE = x° and ∠CEF = 130°, then x = ?


According to question,
AB || EF
EF || CD (AB is produced to F, CF is traversal)
FEC=130o
Now,
BFC +
BFO = 180o(Sum of angles of Linear pair is 180o)
BFO = 180o – 130o = 50o
Now in triangle BOF, we have
ABO =
BFO +
BOF
85 = 50 +
BOF
BOF = 85 – 50 =35o
So, x = o
Couldn't generate an explanation.
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