Q23 of 153 Page 148

In the given figure, AB || CD. If ∠AOC = 30° and ∠OAB = 100°, then ∠OCD = ?

From O, draw E such that OE || CD || AB.


OE || CD and OC is traversal.


So,


DCO + COE = 180 (co –interior angles)


x + COE = 180


COE = (180 – x)


Now, OE || AB and AO is the traversal.


BAO + AOE = 180 (co –interior angles)


BAO + AOC + COE = 180


100 + 30 + (180 – x) = 180


180 – x = 50


X = 180 – 50 = 130O

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