Q43 of 153 Page 148

In ΔABC, BD ⊥ AC, ∠CAE = 30° and ∠CBD = 40°. Then ∠AEB = ?

In triangle BDC,


∠B= 40, ∠D = 90


So, ∠C = 180 –(90 + 40)


= 50°


Now in triangle AEC,


∠C= 50, ∠A = 30


So, ∠E = 180 – (50 + 30)


= 100°


Thus, ∠AEB = 180 – 100 (Sum of linear pair is 180°)


= 80°

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