Q44 of 153 Page 148

In the given figure, AB || CD, CD || EF and y : z = 3 : 7, then x = ?

Let n be the common multiple.

Y + Z = 180

3n + 7n = 180

N =18

So, y = 3n = 54^o

z = 7n = 126^o

x = z (Pair of alternate angles)

So, x = 126^o

In the given figure, sides CB and BA of ΔABC have been produced to D and E respectively such that ∠ABD = 110° and ∠CAE = 135°. Then ∠ACB = ?

In ΔABC, BD ⊥ AC, ∠CAE = 30° and ∠CBD = 40°. Then ∠AEB = ?

In the given figure, AB || CD || EF, EA ⊥ AB and BDE is the transversal such that ∠DEF = 55°. Then ∠AEB = ?

In the given figure, AM ⊥ BC and AN is the bisector of ∠A. If ∠ABC = 70° and ∠ACB = 20°, then ∠MAN = ?