In the given figure, AB || CD. If ∠APQ = 70° and ∠PRD = 120°, then ∠QPR = ?


APQ =
PQR =70o
Now, in triangle PQR, we have
PQR +
PRQ +
QPQ =180o
70 + 60 +
QPQ =180o
QPQ =180o – 130o
=50o
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