Q3 of 153 Page 118

In the adjoining figure, AOB is a straight line. Find the value of x. Hence, find,and .

X=32, =103°, ∠COD =45°=32°


AOB is a straight line


Therefore, + ∠COD + = 180°


⇒ (3x + 7)° + (2x - 19)° + x° = 180°


⇒ 3x + 7° + 2x - 19° + x° = 180°


⇒ 6x = 180° + 12°


⇒ 6x = 192°


⇒ x = 32°


= (3x + 7)°


= 3×32° + 7 = 103°


∠COD = (2x - 19)°


= 2×32° – 19 = 45°


= x


= 32°


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