Q16 of 153 Page 166

In the given figure AB || CD, ∠APQ = 50° and ∠PRD = 120°. Find ∠QPR.

According to question,

PRD = 120^O

PRD = APR (Pair of alternate interior angles)

So,

APR = 120

APQ + QPR = 120

50 + QPR = 120

QPR = 120 – 50

= 70^O

Match the following columns:

Column I	Column II
(a) An angle is 10° more than its complement. The measure of the angle is….	(p) 160°
(b) In ΔABC, ∠A = 65° and ∠B – ∠C = 25°, then ∠B = …	(q) 50°
(c) In ΔABC, ∠A = 40° and ∠B = ∠C? If EF \|\| BC, then ∠EFC = …	(r) 70°
(d) If the angles around a point are 2x°, 3x°, 5x° and 40° then the measure of largest angle is……….	(s) 110°

The correct answer is:

A. – …….., B. – ……….,

C. – ………, D. – ……….,

In the given figure, lines AB and CD intersect at O such that ∠AOD + ∠BOD + ∠BOC = 300°. Find ∠AOD.

In the given figure, BE is the bisector of ∠B and CE is the bisector of ∠ACD.

Prove that

In ΔABC, sides AB and AC are produced to D and E respectively. BO and CO are the bisectors of ∠CBD and ∠BCE respectively. Then, prove that