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4. Angles, Lines and Triangles
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Q39 of 153 Page 148

In the given figure, AB || DC, ∠BAD = 90°, ∠CBD = 28° and ∠BCE = 65°. Then ∠ABD = ?

∠BCE = ∠ABC =65o (Alternate Angles)


∠ABC = ∠ABD + ∠DBC


65o = ∠ABD + 28o


∠ABD = 65 – 28


= 37o

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Questions · 153
4. Angles, Lines and Triangles
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