Q5 of 153 Page 129

In the given figure, AB||CD ||EF. Find the value of x.

X=20


Given AB||CD||EF, ∠ABC = 70° and ∠CEF = 130°


AB||CD


Therefore,


∠ABC = ∠BCD = 70° [Alternate angles] ________________ (i)


EF||CD


Therefore,


∠DCE + ∠CEF = 180°


⇒ ∠DCE + 130° = 180°


⇒ ∠DCE = 50°


Now,


∠BCE + ∠DCE = ∠BCD


⇒ x + 50° = 70°


⇒ x = 20°


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