Q36 of 153 Page 148

In the given figure, ∠OAB = 75°, ∠OBA = 55° and ∠OCD = 100°. Then ∠ODC = ?

In triangle AOB,

∠AOB =180^o – 75^o – 55^o

= 50^o

∠AOB = ∠COD = 50^o(Opposite angles)

Now in triangle COD,

∠ODC =180^o – 100^o – 50^o

= 30^o

In the given figure, BO and CO are the bisectors of ∠B and ∠C respectively. If ∠A = 50°, then ∠BOC = ?

In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = ?

In a ΔABC its is given that ∠A : ∠B : ∠C = 3 : 2 : 1 and CD ⊥ AC. Then ∠ECD = ?

In the given figure, AB || CD. If ∠ABO = 45° and ∠COD = 100° then ∠CDO = ?