In the given figure, AB || CD, ∠BAD = 30° and ∠ECD = 50°. Find ∠CED.

A =
D (Pair of alternate angles)
= 30O
Now, in triangle EDC we have
D = 30O and
C = 50O
So,
CED = 180 – (
C +
D)
= 180 – 30 – 50
=100O
Couldn't generate an explanation.
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