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4. Angles, Lines and Triangles
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Q10 of 153 Page 166

In the given figure, AB || CD, ∠BAD = 30° and ∠ECD = 50°. Find ∠CED.

A = D (Pair of alternate angles)


= 30O


Now, in triangle EDC we have


D = 30O and C = 50O


So,


CED = 180 – (C + D)


= 180 – 30 – 50


=100O


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Questions · 153
4. Angles, Lines and Triangles
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