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Mathematics
4. Angles, Lines and Triangles
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Q8 of 153 Page 129

In the given figure, AB||CD and BC||ED. Find the value of x.

X=105


Given AB||CD and BC||ED.



AB||CD


Therefore, ∠BCF = ∠EDC = 75° [Crossponding angles]


∠ABC + ∠BCF = 180° [Because AB||DCF]


⇒ x + 75° = 180°


⇒ x = 105°


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Questions · 153
4. Angles, Lines and Triangles
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