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4. Angles, Lines and Triangles
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Q24 of 153 Page 148

In the given figure, AB || CD. If ∠CAB = 80° and ∠EFC = 25°, then ∠CEF = ?

AB || CD


BAC = DCF = 80o


ECF + DCF = 180o (linear pair of angles)


ECF =100o


Now in triangle CFE,


ECF + EFC + CEF = 180o


CEF = 180o – 100o – 25o


=55o

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Questions · 153
4. Angles, Lines and Triangles
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