In the given figure, AB || CD. If ∠CAB = 80° and ∠EFC = 25°, then ∠CEF = ?

AB || CD
BAC =
DCF = 80o
ECF +
DCF = 180o (linear pair of angles)
ECF =100o
Now in triangle CFE,
ECF +
EFC +
CEF = 180o
CEF = 180o – 100o – 25o
=55o
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