Determine whether x = √3 and x = —2√3 are solutions of the equation x2 – 3√3x + 6 = 0
Put both the values of x in the equation.
When x = √3
(√3)2 –3√3(√3) + 6 = 0
3 – (3)3 + 6
3 – 9 + 6
9 – 9
= 0
Therefore, it is the solution to the equation.
When x = –2√3
(–2√3)2 –3√3(–2√3) + 6 = 0
12 + 18 + 6
= 36
Therefore, it is not the solution to the equation.
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