The denominator of a fraction exceeds its numerator by 3. If 3 is added to both numerator and denominator, the difference between the new and the original fraction is
. Find the original fraction.
Let the denominator be ‘(X+3)’, so the numerator will be ‘X’.
the original fraction is ![]()
the new fraction is ![]()
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On simplifying further,
![]()
88(9) = 9(X2 + 9X + 18)
X2 + 9X – 70 = 0 –––––– (i)
On applying Sreedhracharya formula
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X = –14 or 5.
the numerator is X = 5 and denominator (X+3) will be 8 and the fraction will be
, as taking (–14) will form a fraction i.e.,
(not satisfying the conditions) .
Couldn't generate an explanation.
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