a2b2x2 + b2x – a2x — 1 = 0, a ≠ 0, b ≠ 0
b2x {a2x + 1} – 1 {a2x + 1} = 0
(b2x – 1) (a2x + 1) = 0
b2x – 1 = 0 a2x + 1 = 0
![]()
Therefore, the roots of the equation are
.
AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.