The numerator of a fraction is 3 less than denominator. If 2 is added to both 29 numerator as well as denominator, then sum of the new and original fraction is
. Find the fraction.
Let the denominator be ‘(X+3)’, so the numerator will be ‘X’.
the original fraction is ![]()
the new fraction is ![]()
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On simplifying further,
![]()
15(2X2 + 10X + 6) = 19(X2 + 8X + 15)
30X2 + 150X + 90 = 19X2 + 152X + 285
11X2 – 2X – 195 = 0 –––––– (i)
On applying Sreedhracharya formula
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∴ it does not have real values.
Couldn't generate an explanation.
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