Find the roots of the following quadratic equations by factorisation:
√7 y2 – 6y — 13√7 = 0
√7 y2 – 13y + 7y — 13 √7 = 0
y (√7 y – 13) + √7 (√7 y – 13) = 0
(√7 y – 13) (y + √7) = 0
√7 y – 13 = 0 y + √7 = 0
y = –√7
Rationalise

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Therefore, the roots of the equation are
,
.
Couldn't generate an explanation.
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