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7. Quadratic Equations
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Q7 of 168 Page 7

Show that x = — 3 is a solution of 2x2 + 5x –3 = 0.

Put x = –3 in the equation.


2(–3)2 + 5(–3) –3 = 0


18 – 15 –3


18 – 18


= 0


Therefore, x = –3 is the solution of the equation.


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5

Determine whether (i) x= √2, (ii) x = –2√2 are the solutions of the equation x2 + √2 x – 4 = 0 or not.

6

Show that x = — 3 is a solution of x2 + 6x + 9 = 0.

8

Show that x = — 2 is a solution of 3x2 + 13x + 14 = 0.

9

For what value of k, is the solution of the equation

kx2 – x – 2 = 0.

Questions · 168
7. Quadratic Equations
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