Q49 of 168 Page 7

Two pipes running together can fill a cistern in minute. If one pipe takes 1 minutes more than the other to fill the cistern, find the time in which each pipe would fill the cistern.

Let the first pipe fill the cistern in ‘X’ minutes, then the second pipe requires ‘(X+1)’ minutes to fill it.


Applying the concept of Unitary Method,


In one minute, both pipes will fill the part of cistern as below:





60X + 30 = 11X2 + 11X


11X2 – 49X – 30 = 0


On applying Sreedhracharya formula







X = – or X = 5


The time required to fill the cistern is 5 & 6 minutes respectively. (as only positive values are considered).


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