The denominator of a fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is
, find the fraction.
Let the numerator be ‘X’, so the denominator will be ‘(2X+1)’.
the fraction is ![]()
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On simplifying further,
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21(5X2 + 4X + 1) = 58 (2X2 + X)
105X2 + 84X + 21 = 116X2 + 58X
11X2 – 26X – 21 = 0–––––– (i)
On applying Sreedhracharya formula
![]()

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X=
or 3
∴ X = 3 (Only positive values)
∴ Numerator is = 3 & denominator is (2X+1) = 7
∴ The fraction is
.
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