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7. Quadratic Equations
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Q15 of 168 Page 7

12abx2 — (9a2 — 8b2) x — 6ab = 0

12abx2 — 9a2 x— 8b2x — 6ab = 0


3ax (4bx – 3a) + 2b (4bx – 3a) = 0


3ax + 2b =0 4bx – 3a =0



Therefore, roots of the equation are, .


More from this chapter

All 168 →
15

36x2 — 12ax + (a2 — b2) = 0

15

10ax2 — 6x + 15ax – 9 = 0, a ≠ 0

15

4x2 — 2 (a2 + b2) x + a2b2 = 0

16

Find the roots of the following quadratic equations, if they exist by the method of completing the square:

5x2 – 6x – 2 = 0

Questions · 168
7. Quadratic Equations
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