Q11 of 168 Page 7

Find the values of k, for which the given equation has real roots:

kx2 — 6x — 2 = 0

Roots are equal


∴ d = 0


d = b2 – 4ac


d = (–6)2 – 4 (–2) (k)


d = 36 + 8k


Put d = 0


0 = 36 + 8k


–8k = 36




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