The numerator of a fraction is 3 more than its denominator. If its reciprocal is subtracted from it, the difference is
. Find the fraction.
Let the denominator be ‘X’, so the numerator will be ‘(X+3)’.
the fraction is ![]()
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On simplifying further,
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28(6X + 9) = 33(X2 + 3X)
168X + 252 = 33X2 + 99X
33X2 – 69X – 252 = 0
11X2 – 13X – 84 = 0 –––––– (i)
On applying Sreedhracharya formula
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it does not have any real values.
Couldn't generate an explanation.
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