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7. Quadratic Equations
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Q2 of 168 Page 7

Two numbers differ by 3 and their product is 504. Find the numbers.

Let the first number be ‘X’, so the other number will be ’(X+3)’.


∵ X(X + 3) = 504


X2 + 3X– 504=0


On applying Sreedhracharya formula







X = –24 or 21.


∴ if the first number is – 24 , then the other number is – 21.


∴ if the first number is 21 , then the other number is 24.


∴ The numbers are not (21,24) & (– 21, – 24).


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Questions · 168
7. Quadratic Equations
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