10ax2 — 6x + 15ax – 9 = 0, a ≠ 0

Q15 of 168 Page 7

10ax² — 6x + 15ax – 9 = 0, a ≠ 0

2x (5ax – 3) + 3 (5ax – 3) = 0

2x+3 =0 5ax – 3 = 0

Therefore, roots of the equation are, .

a²b²x² + b²x – a²x — 1 = 0, a ≠ 0, b ≠ 0

36x² — 12ax + (a² — b²) = 0

12abx² — (9a² — 8b²) x — 6ab = 0

4x² — 2 (a² + b²) x + a²b² = 0