Q14 of 168 Page 7

Find the roots of the following quadratic equations by factorisation:

Now, to find the roots by factorisation, we need to factorise 10 such that the sum is 10 and the product is 7√3 × √3 = 21


We can do that by 7 and 3.


So,


√3x2 + 10x + 7√3 = 0


√3x2 + 3x + 7x + 7√3 = 0


√3x(x + √3) + 7(x + √3) = 0


(√3x + 7)(x + √3) = 0


(√3x + 7) = 0




Or


x + √3 = 0


x = -√3


Hence, the solutions of the given quadratic equations are -√3 and .


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