Q15 of 168 Page 7

36x2 — 12ax + (a2 — b2) = 0

(6x)2 – 2 (6x)a + a2 — b2 = 0


Using Identity:


(x– y)2 = x2 + y2 – 2xy


Here, (6x–a)2 = (6x)2 – 2 (6x) a + a2


(6x – a)2 – b2 = 0


Using identity:


x2 – y2 = (a+ b) (a – b)


(6x –a + b) (6x – a – b) =0


6x = a – b 6x = a + b



Therefore, the roots of the equation are,


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