Find the values of k, for which the given equation has real roots:
kx2+ 4x + 1 = 0
Roots are equal
∴ d = 0
d = b2 – 4ac
d = (4)2 – 4 (1) (k)
d = 16 – 4k
Put d = 0
0 = 16 – 4k
4k = 16
k = 4
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