Q1 of 227 Page 73

Solve the following system of equation by elimination method.
x + 2y = 7, x – 2y = 1

The given equations are

x + 2y = 7 … (1)

x – 2y = 1 … (2)

Adding (1) and (2),

⇒ x + 2y + x – 2y = 7 + 1

⇒ 2x = 8

⇒ x = 4

Substituting x = 4 in (1),

⇒ 4 + 2y = 7

⇒ 2y = 7 – 4 = 3

⇒ y =

∴ (4,) is the solution to the given system.

Solve the following system of equation by elimination method.

3x + y = 8, 5x + y = 10

Solve the following system of equation by elimination method.

11x – 7y = xy, 9x – 4y = 6xy

Solve the following system of equation by elimination method.

Solve the following system of equation by elimination method.x + 2y = 7, x – 2y = 1