Q1 of 227 Page 82

Find the zeros of the following quadratic polynomials and verify the basic relationships between the zeros and the coefficients.

x2 – 2x – 8

Let f(x) = x2 – 2x – 8

To find out zeros of the given polynomial.


We put f(x) = 0


x2 – 2x – 8 = 0


To find out roots of this polynomial we use splitting of middle term method.


According to this method we need to find two numbers whose sum is – 2 and product is 8.


x2 – (4 – 2)x – 8 = 0


x2 – 4x + 2x – 8 = 0


x(x – 4) + 2(x – 4) = 0


(x + 2)(x – 4) = 0


x = – 2 and x = 4.


Our zeros are α = – 2 and β = 4.


sum of zeros = α + β = – 2 + 4 = 2.


Product of zeros = αβ = ( – 2) × 4 = – 8.


Comparing f(x) = x2 – 2x – 8 with standard equation ax2 + bx + c = 0.


We get, a = 1, b = – 2 and c = – 8


We can verify,


Sum of zeros =


i.e. α + β =


α + β = 2


Product of zeros =


αβ =


αβ = – 8.


Hence, relationship between zeros and coefficient is verified.


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