Solve the following quadratic equations by factorization method.
3(x2 – 6) =x (x + 7)–3
3(x2 – 6) =x (x + 7)–3
= 3x2 – 18 = x2 + 7x – 3
= 3x2 – 18 – x2 – 7x + 3 = 0
= 2x2 – 7x – 15 = 0
= 2x2 – 10x + 3x – 15 = 0
= 2x(x – 5) + 3(x – 5) = 0
= (2x + 3)(x – 5) = 0
2x + 3 = 0 or x – 5 = 0
2x = –3 or x = 5
or x = 5
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