If one root of the equation 2x2 – ax + 64 = 0 is twice the other, then find the value of a
Roots of any quadratic equation are α and β
Here one root is twice the other.
α = 2β
by comparing the given equation with general form of quadratic equation we get,
a = 2, b = –a and c = 64
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α + β = ![]()
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…(1)
αβ = 32
2β(β) = 32
2β2 = 32
⇒ ![]()
⇒ β2 = 16
⇒ β = √16
⇒ β =± 4
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⇒ 12 × 2 = a
⇒ a = 24
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