Q2 of 227 Page 89

Find the GCD of the following

x4 – 27a3 x,(x – 3a)2

Given,


x4 – 27a3 x = x[x3 – (3a)3]


= x[(x – 3a)(x2 + 9a2 + 3ax)]


= x(x – 3a)(x2 + 9a2 + 3ax)


(x – 3a)2 = (x – 3a)(x – 3a)


Greatest common divisor = (x – 3a)


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