The sum of a number and its reciprocal is
. Find the number.
Let x be the required number. Then, the reciprocal is
.
⇒ sum of a number and its reciprocal is ![]()
⇒ ![]()
⇒ ![]()
⇒ 8(x2 + 1) = 65x
⇒ 8x2 + 8 = 65x
⇒ 8x2 – 65x + 8 = 0
⇒ 8x2 – x – 64x + 8 = 0
⇒ x(8x – 1) – 8(8x – 1) = 0
⇒ (x – 8) (8x – 1) = 0
x – 8 = 0 or 8x – 1 = 0
x = 8 or 8x = 1
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Therefore, the two required numbers are 8 and
.
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