Factorize each of the following polynomials.
x3 – 2x2 – 5x + 6
Given,
x3 – 2x2 – 5x + 6, put x = 1
then, 1 – 2 – 5 + 6 = 0, since,
this equation is divisible by (x – 1)
according to the question,
x3 – 2x2 – 5x + 6 = (x – 1)(x2 – x – 6)
= (x – 1)[x2 – 3x + 2x – 6]
= (x – 1)[x(x – 3) + 2(x – 3)]
= (x – 1)(x + 2)(x – 3)
Couldn't generate an explanation.
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